Chris Larson 57044b9a62 Implement ??= operator ... ??= is a lazy, conditional assignment. Whereas a ?= immediately assigns to the variable if the variable has not yet been set, ??= does not apply the default assignment until the end of the parse. As a result, the final ??= for a given variable is used, as opposed to the first as in ?=. Note that the initial implementation relies upon finalise() to apply the defaults, so a "bitbake -e" without specifying a recipe will not show the defaults as set by ??=. Moving application of the default into getVar adds too large a performance hit. We may want to revisit this later. (Bitbake rev: 74f50fbca194c9c72bd2a540f4b9de458cb08e2d) Signed-off-by: Chris Larson <chris_larson@mentor.com> Signed-off-by: Richard Purdie <rpurdie@linux.intel.com>		2010-03-22 15:02:59 +00:00
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manual	Implement ??= operator	2010-03-22 15:02:59 +00:00
bitbake.1	bitbake: Switch to bitbake-dev version (bitbake master upstream)	2010-01-20 18:46:02 +00:00
COPYING.GPL	bitbake: Sync with upstream.	2007-01-08 23:53:01 +00:00
COPYING.MIT	Initial population	2005-08-31 10:47:56 +00:00